Which of the following bonds has the most pol | vedclass

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(D) The polarity of a covalent bond depends on the difference in electronegativity between the two bonded atoms.Greater the difference in electronegat

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$C-F$

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(D) The polarity of a covalent bond depends on the difference in electronegativity between the two bonded atoms.Greater the difference in electronegativity,higher is the polarity of the bond.The electronegativity values of the atoms involved are: $C = 2.55$,$O = 3.44$,$Br = 2.96$,$S = 2.58$,and $F = 3.98$.The differences in electronegativity are:$C-O: |3.44 - 2.55| = 0.89$$C-Br: |2.96 - 2.55| = 0.41$$C-S: |2.58 - 2.55| = 0.03$$C-F: |3.98 - 2.55| = 1.43$Since the difference in electronegativity is highest for the $C-F$ bond,it has the most polar character.Therefore,the correct option is $(D)$.

Which of the following bonds has the most polar character?

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