Which of the following carbocations will not | vedclass

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Question

(B) Rearrangement of carbocations occurs to form a more stable carbocation (e.g.,primary to secondary,or secondary to tertiary,or resonance-stabilized

Vedclass · Accepted Answer

$1-$Phenyl$-1-$propyl carbocation

Vedclass · Answer

(B) Rearrangement of carbocations occurs to form a more stable carbocation (e.g.,primary to secondary,or secondary to tertiary,or resonance-stabilized). $A$. The isobutyl carbocation $(CH_3)_2CH-CH_2^+$ is a primary carbocation that undergoes a $1,2$-hydride shift to form a more stable tertiary carbocation $(CH_3)_2C^+-CH_3$. $B$. The $1$-phenyl-$1$-propyl carbocation $(Ph-CH^+-CH_2-CH_3)$ is already resonance-stabilized by the phenyl ring and is a secondary carbocation. It does not undergo further rearrangement because it is already highly stable. $C$. The $2$-ethylcyclohexyl carbocation is a secondary carbocation that can undergo ring expansion or hydride shifts to form more stable carbocations. $D$. The $2-(1,2,3,4-tetrahydronaphthalen-2-yl)ethyl$ carbocation is a primary carbocation that can undergo rearrangement to form a more stable secondary or tertiary carbocation. Therefore,the $1$-phenyl-$1$-propyl carbocation is the most stable among the options and does not undergo rearrangement.

Which of the following carbocations will not undergo rearrangement?

Similar Questions

The number of hyperconjugation structures involved to stabilize the carbocation formed in the above reaction is $.............$.

Stability order of the following carbocations:
$(i) CH_3 - C^{+}(OCH_3) - CH_3$
$(ii) CH_3 - C^{+}(CH_3) - CH_3$
$(iii) CH_3 - NH - C^{+}H_2$
$(iv) CH_3 - C^{+}H_2$

Which free radical from the following is least stable?

What type of reaction is oxidative rancidity?

The correct order of stability of the following carbocations is:

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