Which of the following complexes has a shape | vedclass

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(D) To determine the shape,we analyze the hybridization of each complex:$1$. $[Zn(NH_3)_4]^{2+}$: $Zn^{2+}$ has a $d^{10}$ configuration. It undergoes

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$[Cu(NH_3)_4]^{2+}$

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(D) To determine the shape,we analyze the hybridization of each complex:$1$. $[Zn(NH_3)_4]^{2+}$: $Zn^{2+}$ has a $d^{10}$ configuration. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$2$. $[Ni(CO)_4]$: $Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$3$. $[Cu(CN)_4]^{3-}$: $Cu^+$ has a $d^{10}$ configuration. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$4$. $[Cu(NH_3)_4]^{2+}$: $Cu^{2+}$ has a $d^9$ configuration. It undergoes $dsp^2$ hybridization,resulting in a square planar geometry.Thus,$[Cu(NH_3)_4]^{2+}$ has a square planar shape,while the others are tetrahedral.

List-$I$ (Hybridisation)	List-$II$ (Compound/ion)
$A. sp^3d$	$I. [PtCl_4]^{2-}$
$B. sp^3d^2$	$II. SF_6$
$C. dsp^2$	$III. BCl_3$
$D. dsp^3$	$IV. PCl_5$
	$V. ClF_3$

Which of the following complexes has a shape different from the others?

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The geometry of the cuprammonium ion $[Cu(NH_3)_4]^{2+}$ is:

$[FeF_6]^{3-}$ has $Fe$ atom . . . . . . hybridised with unpaired . . . . . . electrons.

Match the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion)
$A. sp^3d$ $I. [PtCl_4]^{2-}$
$B. sp^3d^2$ $II. SF_6$
$C. dsp^2$ $III. BCl_3$
$D. dsp^3$ $IV. PCl_5$
$V. ClF_3$

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Define the following term: Coordination polyhedron.

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