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(D) According to Werner's theory,the chloride ions present outside the coordination sphere (ionizable chlorides) react with $AgNO_3$ to form $AgCl$ pr

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One mole of $PtCl_4 \cdot 3 NH_3$

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(D) According to Werner's theory,the chloride ions present outside the coordination sphere (ionizable chlorides) react with $AgNO_3$ to form $AgCl$ precipitate.$1$. $PtCl_4 \cdot 4 NH_3$ can be written as $[Pt(NH_3)_4Cl_2]Cl_2$,which gives $2$ moles of $AgCl$.$2$. $PtCl_4 \cdot 5 NH_3$ can be written as $[Pt(NH_3)_5Cl]Cl_3$,which gives $3$ moles of $AgCl$.$3$. $PtCl_4 \cdot 2 NH_3$ can be written as $[Pt(NH_3)_2Cl_4]$,which gives $0$ moles of $AgCl$.$4$. $PtCl_4 \cdot 3 NH_3$ can be written as $[Pt(NH_3)_3Cl_3]Cl$,which gives $1$ mole of $AgCl$.Therefore,the complex that gives only one mole of $AgCl$ is $PtCl_4 \cdot 3 NH_3$.

Formula of the complexes	Moles of $AgCl$ precipitated per mole of complex
$(I) \ CoCl_3 \cdot 6 H_2O$	$3$
$(II) \ NiCl_3 \cdot 6 H_2O$	$2$
$(III) \ Co(SO_4)Br \cdot 5 NH_3$	$1$

Which of the following complexes gives only one mole of $AgCl$ when reacted with excess $AgNO_3$?

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