Which of the following complexes is paramagne | vedclass

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(D) To determine the magnetic nature,we calculate the number of unpaired electrons in each complex:$1$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $d^6$. $NH

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$[NiCl_4]^{2-}$

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(D) To determine the magnetic nature,we calculate the number of unpaired electrons in each complex:$1$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $d^6$. $NH_3$ is a strong field ligand,causing pairing. All electrons are paired,so it is diamagnetic.$2$. In $[Ni(CO)_4]$,$Ni$ is $d^8 s^2$. $CO$ is a strong field ligand,causing $4s$ electrons to pair into $3d$. All electrons are paired,so it is diamagnetic.$3$. In $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,causing pairing in $3d$ orbitals. All electrons are paired,so it is diamagnetic.$4$. In $[NiCl_4]^{2-}$,$Ni^{2+}$ is $d^8$. $Cl^-$ is a weak field ligand,so no pairing occurs. There are $2$ unpaired electrons in the $3d$ orbitals,making it paramagnetic.

Which of the following complexes is paramagnetic?

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