Which of the following compounds has the smal | vedclass

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(D) For series $(A)$,as the electronegativity of the halogen decreases,the electron density around the central atom increases,leading to greater repul

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$OSF_2, SbCl_3$ and $SbI_3$

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(D) For series $(A)$,as the electronegativity of the halogen decreases,the electron density around the central atom increases,leading to greater repulsion between the bonding pairs and the lone pair,which decreases the bond angle. Thus,$OSF_2$ has the smallest bond angle.For series $(B)$,as the electronegativity of the halogen decreases,the bond angle increases. Thus,$SbCl_3$ has the smallest bond angle.For series $(C)$,as we move down the group,the central atom size increases and the electronegativity decreases,leading to a decrease in the bond angle. Thus,$SbI_3$ has the smallest bond angle.Therefore,the correct sequence is $OSF_2, SbCl_3$ and $SbI_3$.

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