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(D) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions proceed via a transition state

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$1-$Bromobutane

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(D) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions proceed via a transition state where the nucleophile attacks the carbon atom from the side opposite to the leaving group.As the steric hindrance (bulkiness) near the reactive carbon increases, the rate of $S_N2$ reaction decreases.The order of reactivity for primary alkyl halides is: $CH_3X > R-CH_2X > R_2CH-CH_2X > R_3C-CH_2X$.Comparing the given options:$(A)$ $1$-Bromo-$3$-methylbutane: $CH_3-CH(CH_3)-CH_2-CH_2Br$ (Primary, but branched at $\gamma$-position).$(B)$ $1$-Bromo-$2,2$-dimethylpropane: $(CH_3)_3C-CH_2Br$ (Primary, but highly hindered at $\beta$-position).$(C)$ $1$-Bromo-$2$-methylbutane: $CH_3-CH_2-CH(CH_3)-CH_2Br$ (Primary, but branched at $\beta$-position).$(D)$ $1$-Bromobutane: $CH_3-CH_2-CH_2-CH_2Br$ (Straight-chain primary alkyl halide).Since $1$-Bromobutane has the least steric hindrance among the given options, it exhibits the highest reactivity towards $S_N2$ reaction.

Which of the following compounds has the highest reactivity towards $S_N2$ reaction?

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