Which of the following compounds is obtained | vedclass

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(C) When glucose is treated with dilute nitric acid $(HNO_3)$,both the aldehyde group $(-CHO)$ and the primary alcoholic group $(-CH_2OH)$ are oxidize

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Saccharic acid

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(C) When glucose is treated with dilute nitric acid $(HNO_3)$,both the aldehyde group $(-CHO)$ and the primary alcoholic group $(-CH_2OH)$ are oxidized to carboxylic acid groups $(-COOH)$.This reaction results in the formation of a dicarboxylic acid known as saccharic acid (also called glucaric acid).The reaction is represented as:$CHO-(CHOH)_4-CH_2OH + [O] \xrightarrow{Dil. HNO_3} COOH-(CHOH)_4-COOH$Thus,the correct product is saccharic acid.

Which of the following compounds is obtained when glucose is treated with dilute nitric acid?

Similar Questions

Statement $I$. Despite having an aldehyde group,glucose does not give the Schiff test.
Statement $II$. Glucose exists in $\alpha$ and $\beta$ crystalline forms.

Assertion : Sucrose is a non-reducing sugar.
Reason : It has glycosidic linkage.

The given osazone can be obtained by:

Which of the following statements is incorrect?

Sucrose is not a reducing sugar since

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