Which of the following compounds is the most | vedclass

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(C) According to Fajan's rule,the covalent character of a compound increases with the increase in the oxidation state of the metal cation. Higher oxid

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$SnCl_4$

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(C) According to Fajan's rule,the covalent character of a compound increases with the increase in the oxidation state of the metal cation. Higher oxidation state leads to higher polarising power of the cation,which results in greater covalent character. Comparing the oxidation states of the metals in the given compounds: $SbCl_3$: $Sb$ is in $+3$ oxidation state. $PbCl_2$: $Pb$ is in $+2$ oxidation state. $SnCl_4$: $Sn$ is in $+4$ oxidation state. $SnCl_2$: $Sn$ is in $+2$ oxidation state. Since $Sn$ in $SnCl_4$ has the highest oxidation state $(+4)$,it has the highest polarising power and thus $SnCl_4$ is the most covalent compound among the given options.

Which of the following compounds is the most covalent?

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