Which of the following curves is correct?

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(D) The relationship between the equilibrium constant $K_{eq}$ and temperature $T$ is given by the van't Hoff equation: $\ln K_{eq} = -\frac{\Delta H^

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(D) The relationship between the equilibrium constant $K_{eq}$ and temperature $T$ is given by the van't Hoff equation: $\ln K_{eq} = -\frac{\Delta H^{\circ}}{R} \left( \frac{1}{T} \right) + \frac{\Delta S^{\circ}}{R}$.Comparing this with the linear equation $y = mx + c$,where $y = \ln K_{eq}$,$x = 1/T$,slope $m = -\frac{\Delta H^{\circ}}{R}$,and intercept $c = \frac{\Delta S^{\circ}}{R}$.For an endothermic reaction,$\Delta H^{\circ} > 0$,so the slope $m = -\frac{\Delta H^{\circ}}{R}$ is negative.For an exothermic reaction,$\Delta H^{\circ} Therefore,for $\Delta H^{\circ} = -ve$,the slope is positive,which matches the graph in option $(D)$.

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