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(A) $Fe(OH)_3$ sol is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of

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$NaCl$

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(A) $Fe(OH)_3$ sol is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particles.For a positively charged sol,the coagulating power is determined by the negative ion (anion). The order of coagulating power is: $PO_4^{3-} > SO_4^{2-} > Cl^-$.Since the flocculation value is inversely proportional to the coagulating power,the electrolyte with the lowest charge on the anion will have the maximum flocculation value.Comparing the anions: $Cl^-$ (charge $-1$),$SO_4^{2-}$ (charge $-2$),$PO_4^{3-}$ (charge $-3$).Therefore,$NaCl$ has the lowest coagulating power and the maximum flocculation value.

Expt. No.	Weight of $X$ (in $mg$) added to gold sol	Coagulation
$1$	$24$	Not prevented
$2$	$23$	Not prevented
$3$	$26$	prevented
$4$	$27$	prevented
$5$	$25$	prevented

Which of the following electrolytes will have the maximum flocculation value for $Fe(OH)_3$ sol?

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