Which of the following elements has the highest metallic character?
Element $- IP$

An atom with high electronegativity has

An element has successive ionization enthalpies as $940 \, kJ \, mol^{-1}$ (first),$2080 \, kJ \, mol^{-1}$,$3090 \, kJ \, mol^{-1}$,$4140 \, kJ \, mol^{-1}$,$7030 \, kJ \, mol^{-1}$,$7870 \, kJ \, mol^{-1}$,$16000 \, kJ \, mol^{-1}$ and $19500 \, kJ \, mol^{-1}$. To which group of the periodic table does this element belong?

Consider the following changes:
$M_{(s)} \to M_{(g)}$ ........$(1)$
$M_{(s)} \to M^{2+}_{(g)} + 2e^-$ .......$(2)$
$M_{(g)} \to M^{+}_{(g)} + e^-$ .........$(3)$
$M^{+}_{(g)} \to M^{2+}_{(g)} + e^-$ .........$(4)$
$M_{(g)} \to M^{2+}_{(g)} + 2e^-$ ..........$(5)$
The second ionization energy of $M$ could be calculated from the energy values associated with:

The successive ionisation energy values for an element $X$ are given below. Element $X$ belongs to which group?
$1^{st} \text{ IE} = 410 \ kJ \ mol^{-1}$
$2^{nd} \text{ IE} = 820 \ kJ \ mol^{-1}$
$3^{rd} \text{ IE} = 1100 \ kJ \ mol^{-1}$
$4^{th} \text{ IE} = 1500 \ kJ \ mol^{-1}$
$5^{th} \text{ IE} = 3200 \ kJ \ mol^{-1}$

Which one of the following statements is incorrect in relation to ionization enthalpy?