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(C) To find the number of unpaired electrons,we write the electronic configuration for each element:$1$. Fluorine ($F$,$Z=9$): $1s^2 2s^2 2p^5$. The $

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Nitrogen

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(C) To find the number of unpaired electrons,we write the electronic configuration for each element:$1$. Fluorine ($F$,$Z=9$): $1s^2 2s^2 2p^5$. The $2p$ subshell has $5$ electrons,resulting in $1$ unpaired electron.$2$. Sodium ($Na$,$Z=11$): $1s^2 2s^2 2p^6 3s^1$. The $3s$ subshell has $1$ unpaired electron.$3$. Nitrogen ($N$,$Z=7$): $1s^2 2s^2 2p^3$. According to Hund's rule,the $2p$ subshell has $3$ electrons in separate orbitals,resulting in $3$ unpaired electrons.$4$. Oxygen ($O$,$Z=8$): $1s^2 2s^2 2p^4$. The $2p$ subshell has $4$ electrons,resulting in $2$ unpaired electrons.Comparing the values,Nitrogen has the maximum number of unpaired electrons $(3)$.

Which of the following elements contains the maximum number of unpaired electrons?

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