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(A) The elevation in boiling point $(\Delta T_b)$ is given by the formula: $\Delta T_b = K_b 	imes m$,where $m$ is the molality of the solution. Mola

Vedclass · Accepted Answer

$M_2 = \frac{1000 	imes K_b 	imes W_2}{\Delta T_b 	imes W_1}$

Vedclass · Answer

(A) The elevation in boiling point $(\Delta T_b)$ is given by the formula: $\Delta T_b = K_b 	imes m$,where $m$ is the molality of the solution. Molality $(m)$ is defined as the number of moles of solute $(n_2)$ per kilogram of solvent $(W_1 	ext{ in grams})$. $m = \frac{n_2 	imes 1000}{W_1} = \frac{W_2 	imes 1000}{M_2 	imes W_1}$. Substituting this into the elevation formula: $\Delta T_b = \frac{K_b 	imes W_2 	imes 1000}{M_2 	imes W_1}$. Rearranging for the molar mass of the solute $(M_2)$: $M_2 = \frac{1000 	imes K_b 	imes W_2}{\Delta T_b 	imes W_1}$.

Which of the following equations correctly represents the molar mass of a solute by knowing the boiling point elevation?

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