Which of the following equations represents the correct relationship between the standard cell potential and the equilibrium constant for a cell reaction?

  • A
    $E_{\text{cell}}^{\circ} = -\frac{2.303 RT}{nF} \log K$
  • B
    $E_{\text{cell}}^{\circ} = \frac{0.0592}{nF} \log_{10} K$
  • C
    $E_{\text{cell}}^{\circ} = \frac{0.0592}{n} \log_{10} K$
  • D
    $E_{\text{cell}}^{\circ} = \frac{0.0592}{n} \ln K$

Explore More

Similar Questions

What is the oxidation potential of $0.05 \, M \, H_2SO_4$ in volts?

What will be the $emf$ for the given cell $Pt|H_2(P_1)|H^{+}_{(aq)}||H_2(P_2)|Pt$?

$Zn_{(s)} + Cl_2(1 \ atm) \to Zn^{2+} + 2Cl^-$. The $E^0_{cell}$ of the cell is $2.12 \ V$. To increase $E_{cell}$:

What is the potential of a half-cell consisting of a zinc electrode in $0.01 \ M$ $ZnSO_4$ solution at $25 \ ^\circ C$ (Given $E^o_{Zn^{2+}/Zn} = -0.763 \ V$) (in $V$)?

For the redox reaction $Zn_{(s)} + Cu^{2+}(0.1 \ M) \to Zn^{2+}(1 \ M) + Cu_{(s)}$ taking place in a cell,$E_{cell}^o$ is $1.10 \ V$. $E_{cell}$ for the cell will be ............ $V$ $\left( 2.303 \frac{RT}{F} = 0.0591 \right)$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo