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(A) To determine the oxidation state of vanadium $(V)$ in each compound,we assign the oxidation states of other elements: $1$. In $VOCl_3$: Let the ox

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$VOCl_3$

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(A) To determine the oxidation state of vanadium $(V)$ in each compound,we assign the oxidation states of other elements: $1$. In $VOCl_3$: Let the oxidation state of $V$ be $x$. Oxygen is $-2$ and Chlorine is $-1$. Thus,$x + (-2) + 3(-1) = 0$,which gives $x - 5 = 0$,so $x = +5$. $2$. In $VCl_4$: $x + 4(-1) = 0$,so $x = +4$. $3$. In $VCl_3$: $x + 3(-1) = 0$,so $x = +3$. $4$. In $VCl_2$: $x + 2(-1) = 0$,so $x = +2$. Comparing these values,the maximum oxidation state of vanadium is $+5$,which is exhibited by $VOCl_3$.

Which of the following exhibits the maximum oxidation state of vanadium?

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