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(A) The equivalent conductance at infinite dilution $(\Lambda_{eq}^{\infty})$ of an electrolyte is the sum of the equivalent conductances of its const

Vedclass · Accepted Answer

$\Lambda_{Al^{3+}}^o + \Lambda_{SO_4^{2-}}^o$

Vedclass · Answer

(A) The equivalent conductance at infinite dilution $(\Lambda_{eq}^{\infty})$ of an electrolyte is the sum of the equivalent conductances of its constituent ions.
By definition,the equivalent conductance of any electrolyte at infinite dilution is the sum of the equivalent conductances of its cation and anion.
For $Al_2(SO_4)_3$,the equivalent conductance at infinite dilution is given by:
$\Lambda_{eq}^{\infty} = \Lambda_{Al^{3+}}^o + \Lambda_{SO_4^{2-}}^o$
This is because the equivalent conductance of an ion is defined as the molar conductance divided by its charge (valence factor),which inherently accounts for the stoichiometry of the salt.

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of $Al_2(SO_4)_3$? Given that $\Lambda_{Al^{3+}}^o$ and $\Lambda_{SO_4^{2-}}^o$ are the equivalent conductances at infinite dilution of the respective ions.

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