Which of the following haloalkanes will under | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of $S_{N}2$ reaction depends primarily on steric hindrance. Less sterically hindered alkyl halides react faster.$(I)$ is $1$-iodopentane

Vedclass · Accepted Answer

$(I)$

Vedclass · Answer

(A) The rate of $S_{N}2$ reaction depends primarily on steric hindrance. Less sterically hindered alkyl halides react faster.$(I)$ is $1$-iodopentane (primary alkyl halide).$(II)$ is $1$-chloropentane (primary alkyl halide).$(III)$ is chlorocyclohexane (secondary alkyl halide).$(IV)$ is (chloromethyl)cyclohexane (primary alkyl halide).Between primary alkyl halides,the nature of the leaving group is important. Iodine is a better leaving group than chlorine because it is a weaker base.Therefore,$1$-iodopentane $(I)$ reacts the fastest in an $S_{N}2$ reaction.

Which of the following haloalkanes will undergo $S_{N}2$ reaction at the fastest rate?

Similar Questions

Heating an aqueous solution of aluminium chloride to dryness will give:

The locus of the complex number $z$ such that $\arg \left(\frac{z-2}{z+2}\right)=\frac{\pi}{3}$ is:

An electric potential difference will be induced between the ends of the conductor shown in the diagram when the conductor moves in the direction:

$4 \ g$ of a hydrocarbon on complete combustion gave $12.571 \ g$ of $CO_2$ and $5.143 \ g$ of water. What is the empirical formula of the hydrocarbon?

If $3x^2-11xy+10y^2-7x+13y+k=0$ denotes a pair of straight lines,then the point of intersection of the lines is

Vedclass Test Series

Exam Paper Generator

Online Exam Module