Which of the following has dsp^2 hybridizatio | vedclass

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(D) To determine the hybridization,we look at the coordination number and the nature of the central metal ion. $NiCl_4^{2-}$ involves $Ni^{2+}$ with a

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$PtCl_4^{2-}$

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(D) To determine the hybridization,we look at the coordination number and the nature of the central metal ion. $NiCl_4^{2-}$ involves $Ni^{2+}$ with a weak field ligand $Cl^-$,resulting in $sp^3$ hybridization (tetrahedral). $SCl_4$ has $sp^3d$ hybridization due to the presence of a lone pair on sulfur. $NH_4^+$ has $sp^3$ hybridization. $PtCl_4^{2-}$ involves $Pt^{2+}$ (a $5d$ series metal),which always forms square planar complexes with strong or weak field ligands due to high crystal field splitting energy,resulting in $dsp^2$ hybridization.

Which of the following has $dsp^2$ hybridization?

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