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(A) The dipole moment $(\mu)$ is defined as the product of the magnitude of the charge $(q)$ and the distance $(d)$ between the charges,given by the f

Vedclass · Accepted Answer

$CH_3Cl > CH_3F > CH_3Br > CH_3I$

Vedclass · Answer

(A) The dipole moment $(\mu)$ is defined as the product of the magnitude of the charge $(q)$ and the distance $(d)$ between the charges,given by the formula $\mu = q 	imes d$.
Although fluorine is more electronegative than chlorine,the $C-Cl$ bond length is significantly larger than the $C-F$ bond length.
This larger bond distance in $CH_3Cl$ outweighs the higher electronegativity of fluorine in $CH_3F$,resulting in a higher dipole moment for $CH_3Cl$ compared to $CH_3F$.
Therefore,the correct order of decreasing dipole moment is $CH_3Cl > CH_3F > CH_3Br > CH_3I$.

Which of the following has been arranged in order of decreasing dipole moment?

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