Which of the following has the highest pH? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $pH$ is defined as $-\log[H^+]$. $A$ higher $pH$ corresponds to a lower concentration of hydrogen ions $[H^+]$.$1$. $0.1 \ M \ HCl$ is a strong ac

Vedclass · Accepted Answer

$0.1 \ M \ CH_3COOH$

Vedclass · Answer

(C) $pH$ is defined as $-\log[H^+]$. $A$ higher $pH$ corresponds to a lower concentration of hydrogen ions $[H^+]$.$1$. $0.1 \ M \ HCl$ is a strong acid,so $[H^+] = 0.1 \ M$,$pH = -\log(0.1) = 1$.$2$. $0.2 \ M \ HCl$ is a strong acid,so $[H^+] = 0.2 \ M$,$pH = -\log(0.2) \approx 0.7$.$3$. $0.15 \ M \ HNO_3$ is a strong acid,so $[H^+] = 0.15 \ M$,$pH = -\log(0.15) \approx 0.82$.$4$. $0.1 \ M \ CH_3COOH$ is a weak acid,so it dissociates partially. The $[H^+]$ will be much less than $0.1 \ M$ (specifically,$[H^+] = \sqrt{K_a 	imes C} \approx \sqrt{1.8 	imes 10^{-5} 	imes 0.1} \approx 1.34 	imes 10^{-3} \ M$).Since the $[H^+]$ for $CH_3COOH$ is the lowest,its $pH$ will be the highest $(pH = -\log(1.34 	imes 10^{-3}) \approx 2.87)$.Therefore,$0.1 \ M \ CH_3COOH$ has the highest $pH$.

Which of the following has the highest $pH$?

Similar Questions

The first and second ionization constants of $H_2X$ are $2.5 \times 10^{-8}$ and $1.0 \times 10^{-13}$ respectively. The concentration of $X^{2-}$ in $0.1 \ M$ $H_2X$ solution is . . . . . . $\times 10^{-15} \ M$. The value of $Y$ is:

The $pH$ of a $0.1 \ M$ solution of a monobasic acid is $2.34$. Calculate the degree of dissociation of the acid.

Find the $pOH$ value of $10^{-3} \ M \ NH_4OH$. Given $K_b = 10^{-5}$.

An organic monobasic acid has a dissociation constant of $2.25 \times 10^{-6}$. What is the percent dissociation in its $0.01 \ M$ solution (in $\%$)?

$A$ monoprotic acid in a $0.1 \ M$ solution ionizes to $0.001 \%$. Its ionisation constant is

Vedclass Test Series

Exam Paper Generator

Online Exam Module