Which of the following has the maximum number | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the number of unpaired electrons,we analyze the electronic configuration in an octahedral field:$1$. For $d^4$ (low spin): The config

Vedclass · Accepted Answer

$d^6$ (high spin)

Vedclass · Answer

(C) To determine the number of unpaired electrons,we analyze the electronic configuration in an octahedral field:$1$. For $d^4$ (low spin): The configuration is $t_{2g}^4 e_g^0$. The number of unpaired electrons is $2$.$2$. For $d^8$ (high spin): The configuration is $t_{2g}^6 e_g^2$. The number of unpaired electrons is $2$.$3$. For $d^6$ (high spin): The configuration is $t_{2g}^4 e_g^2$. The number of unpaired electrons is $4$.Comparing these,$d^6$ (high spin) has the maximum number of unpaired electrons $(4)$.

Which of the following has the maximum number of unpaired electrons?

Similar Questions

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively $:$
$[Fe(CN)_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Mn(CN)_6]^{3-}$

Which one of the following complexes is an outer orbital complex?

Consider the reaction $CuSO_4 + KCN \to CuCN + Y \xrightarrow{\text{excess } K^{+}CN^{-}} Z$. Identify the correct statement regarding the products $Y$ and $Z$.

The magnetic moment of $[MnX_4]^{2-}$ is $5.9 \, BM$. The geometry of the complex ion is: ($X =$ monodentate halide ion)

$A$ complex with the composition $[MA_3B]^{n \pm}$ is found to have no geometrical isomers. The possible structure$(s)$ of the complex is/are (where $A$ and $B$ are monodentate ligands):

Vedclass Test Series

Exam Paper Generator

Online Exam Module