Which of the following has the most unpaired | vedclass

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(B) To determine the number of unpaired $d$-electrons,we look at the electronic configuration of each ion:$Zn^{+}$ $(Z=30)$: $[Ar] \, 3d^{10} 4s^1$. N

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$Fe^{2+}$

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(B) To determine the number of unpaired $d$-electrons,we look at the electronic configuration of each ion:$Zn^{+}$ $(Z=30)$: $[Ar] \, 3d^{10} 4s^1$. Number of unpaired $d$-electrons = $0$.$Fe^{2+}$ $(Z=26)$: $[Ar] \, 3d^6 4s^0$. The $3d^6$ configuration has $4$ unpaired electrons.$N^{3+}$ $(Z=7)$: $1s^2 2s^2 2p^6$. This ion has no $d$-electrons.$Cu^{+}$ $(Z=29)$: $[Ar] \, 3d^{10} 4s^0$. Number of unpaired $d$-electrons = $0$.Comparing these,$Fe^{2+}$ has the most unpaired $d$-electrons $(4)$.

Which of the following has the most unpaired $d$-electrons?

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