(A) $XeF_4$ has a square planar structure because it has $4$ bond pairs and $2$ lone pairs on the central $Xe$ atom,resulting in $sp^3d^2$ hybridizati

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(A) $XeF_4$ has a square planar structure because it has $4$ bond pairs and $2$ lone pairs on the central $Xe$ atom,resulting in $sp^3d^2$ hybridization.$NH_4^+$,$BF_4^-$,and $CCl_4$ all have $4$ bond pairs and $0$ lone pairs,resulting in $sp^3$ hybridization and a tetrahedral structure.

Class 12 Chemistry p-Block Elements (Class 12)Noble gases

Medium

Which of the following has the square planar structure?

AIEEE 2012 All AIEEE

A
$XeF_4$
B
$NH_4^+$
C
$BF_4^-$
D
$CCl_4$

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Noble gases

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The number of $p \pi-d \pi$ 'pi' bonds present in $XeO_3$ and $XeO_4$ molecules,respectively,are

MediumTS EAMCET 2009

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Match the compounds given in Column-$I$ with the shapes given in Column-$II$ and mark the correct option.

Column-$I$ Column-$II$

$(a) XeF_6$ $(i) \text{ Distorted Octahedral}$

$(b) XeO_3$ $(ii) \text{ Square planar}$

$(c) XeOF_4$ $(iii) \text{ Pyramidal}$

$(d) XeF_4$ $(iv) \text{ Square pyramidal}$

Column-$I$	Column-$II$
$(a) XeF_6$	$(i) \text{ Distorted Octahedral}$
$(b) XeO_3$	$(ii) \text{ Square planar}$
$(c) XeOF_4$	$(iii) \text{ Pyramidal}$
$(d) XeF_4$	$(iv) \text{ Square pyramidal}$