Which of the following intermediates is forme | vedclass

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(C) The addition of $HBr$ to propene in the presence of peroxide follows the anti-Markovnikov rule via a free radical mechanism.In the propagation ste

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$CH_3-\dot{C}H-CH_2Br$

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(C) The addition of $HBr$ to propene in the presence of peroxide follows the anti-Markovnikov rule via a free radical mechanism.In the propagation step,the bromine radical $(\dot{B}r)$ attacks the double bond of propene.There are two possibilities for the attack of the bromine radical:$1$. Attack at $C_1$ leads to the formation of a secondary free radical: $CH_3-\dot{C}H-CH_2Br$.$2$. Attack at $C_2$ leads to the formation of a primary free radical: $CH_3-CH(Br)-\dot{C}H_2$.Since a secondary free radical is more stable than a primary free radical,the intermediate $CH_3-\dot{C}H-CH_2Br$ is formed preferentially,leading to the major product $CH_3-CH_2-CH_2Br$.

Which of the following intermediates is formed to produce the major product in the addition of $HBr$ to propene in the presence of peroxide?

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