Which of the following ions has the highest m | vedclass

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(A) Magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)}$ $B$.$M$.,where $n$ is the number of unpaired electrons.$1$. $	ext{Cr}^{2+}:

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$	ext{Cr}^{2+}$

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(A) Magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)}$ $B$.$M$.,where $n$ is the number of unpaired electrons.$1$. $	ext{Cr}^{2+}: [Ar]3d^4 \implies n=4$, $\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90$ $B$.$M$.$2$. $	ext{Ni}^{2+}: [Ar]3d^8 \implies n=2$, $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83$ $B$.$M$.$3$. $	ext{Cu}^{2+}: [Ar]3d^9 \implies n=1$, $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73$ $B$.$M$.$4$. $	ext{Co}^{2+}: [Ar]3d^7 \implies n=3$, $\mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87$ $B$.$M$.Comparing the values, $	ext{Cr}^{2+}$ has the highest number of unpaired electrons $(n=4)$, and therefore, it has the highest magnetic moment.

Which of the following ions has the highest magnetic moment value?

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