Which of the following is 1^{circ} allylic al | vedclass

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(B) An allylic alcohol is one where the $-OH$ group is attached to a carbon atom adjacent to a carbon-carbon double bond $(C=C-C-OH)$. $A$ $1^{\circ}$

Vedclass · Accepted Answer

$CH_2=CH-CH_2-OH$

Vedclass · Answer

(B) An allylic alcohol is one where the $-OH$ group is attached to a carbon atom adjacent to a carbon-carbon double bond $(C=C-C-OH)$. $A$ $1^{\circ}$ allylic alcohol has the $-OH$ group attached to a primary carbon ($CH_2$ group) which is adjacent to a double bond. $1.$ $CH_2=CH-CH(CH_3)-OH$: The $-OH$ is on a secondary carbon,so it is a $2^{\circ}$ allylic alcohol. $2.$ $CH_2=CH-CH_2-OH$: The $-OH$ is on a primary carbon adjacent to the double bond,so it is a $1^{\circ}$ allylic alcohol. $3.$ $CH_2=CH-C(CH_3)_2-OH$: The $-OH$ is on a tertiary carbon,so it is a $3^{\circ}$ allylic alcohol. $4.$ $CH_3-CH=CH-CH_2-CH_2-OH$: The $-OH$ is on a carbon that is not adjacent to the double bond,so it is not an allylic alcohol. Therefore,the correct option is $B$.

Which of the following is $1^{\circ}$ allylic alcohol?

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