Which of the following statements is correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The mole fraction $(x)$ of a component is defined as the ratio of the number of moles of that component to the total number of moles of all compon

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) The mole fraction $(x)$ of a component is defined as the ratio of the number of moles of that component to the total number of moles of all components present in the solution.For a binary solution containing components $I$ and $II$,the sum of mole fractions is $x_I + x_{II} = 1$.Also,the ratio of mole fractions is equal to the ratio of the number of moles: $x_I / x_{II} = n_I / n_{II}$.The mole fraction of a solute is given by $x_{	ext{solute}} = n_{	ext{solute}} / (n_{	ext{solute}} + n_{	ext{solvent}})$.Therefore,all the given statements are correct.

Which of the following statements is correct regarding the mole fraction of components in a solution?

Similar Questions

If the density of a $2.05 \ M$ $CH_3COOH$ solution is $1.02 \ g/mL$,what is the molality of the solution?

Molarity is expressed as

In $500 \ mL$ of $0.2 \ M \ NaCl$ solution,$1500 \ mL$ of $0.4 \ M \ MgCl_2$ solution is mixed. The only incorrect final concentration of ion is (assume volume to be additive)

The mass $\%$ of urea solution is $6$. The total weight of the solution is $1000 \ g$. What is its concentration in $mol \ L^{-1}$? (Density of water $= 1.0 \ g \ mL^{-1}$)
$(C = 12 \ u, N = 14 \ u, O = 16 \ u, H = 1 \ u)$

$A$ $6.50$ molal solution of $KOH$ $(aq.)$ has a density of $1.89 \ g \ cm^{-3}$. The molarity of the solution is .......... $mol \ dm^{-3}$.
(Round off to the Nearest Integer).
[Atomic masses: $K = 39.0 \ u, O = 16.0 \ u, H = 1.0 \ u$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module