Which of the following is correct?

  • A
    $\sin 1 > \sin 2 > \sin 3$
  • B
    $\sin 1 < \sin 2 < \sin 3$
  • C
    $\sin 1 < \sin 3 < \sin 2$
  • D
    $\sin 3 < \sin 1 < \sin 2$

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The expression $[1 - \sin(3\pi - \alpha) + \cos(3\pi + \alpha)] [1 - \sin(\frac{3\pi}{2} - \alpha) + \cos(\frac{5\pi}{2} - \alpha)]$ when simplified reduces to:

Difficult
View Solution

$\frac{1}{\sin 250^{\circ}}+\frac{\sqrt{3}}{\cos 290^{\circ}} = $

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