Which of the following is correctly matched?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let us analyze each complex:$1$. $[Cu(NH_3)_4]^{2+}$: $Cu^{2+}$ is $3d^9$. It has one unpaired electron,so it is paramagnetic.$2$. $[Ni(CN)_4]^{2-

Vedclass · Accepted Answer

$[Fe(CN)_6]^{4-}$ Diamagnetic

Vedclass · Answer

(D) Let us analyze each complex:$1$. $[Cu(NH_3)_4]^{2+}$: $Cu^{2+}$ is $3d^9$. It has one unpaired electron,so it is paramagnetic.$2$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing. It is diamagnetic.$3$. $[MnCl_4]^{2-}$: $Mn^{2+}$ is $3d^5$. $Cl^-$ is a weak field ligand. It has five unpaired electrons,so it is paramagnetic.$4$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing of electrons in $t_{2g}$ orbitals. It is diamagnetic.Thus,the correct match is $[Fe(CN)_6]^{4-}$ Diamagnetic.

Similar Questions

Mass $M$ is divided into two parts $xM$ and $(1-x)M$. For a given separation,the value of $x$ for which the gravitational attraction between the two pieces becomes maximum is

$\sum_{k=1}^{\infty} \frac{1}{k!}\left(\sum_{n=1}^k 2^{n-1}\right)$ is equal to

The mass defect for the nucleus of helium is $0.0303 \, a.m.u.$ What is the binding energy per nucleon for helium in $MeV$?

Transition elements form complex compounds due to:

The idea of secondary wavelets for the propagation of a wave was first given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module