Which of the following is the dimensional for | vedclass

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(C) The formula for the coefficient of viscosity $\eta$ is given by Newton's law of viscosity: $F = \eta A \frac{dv}{dx}$.Rearranging for $\eta$,we ge

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$[ML^{-1}T^{-1}]$

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(C) The formula for the coefficient of viscosity $\eta$ is given by Newton's law of viscosity: $F = \eta A \frac{dv}{dx}$.Rearranging for $\eta$,we get $\eta = \frac{F \cdot dx}{A \cdot dv}$.The dimensions are: Force $F = [MLT^{-2}]$,Area $A = [L^2]$,distance $dx = [L]$,and velocity $dv = [LT^{-1}]$.Substituting these into the formula: $\eta = \frac{[MLT^{-2}][L]}{[L^2][LT^{-1}]}$.Simplifying the expression: $\eta = \frac{[ML^2T^{-2}]}{[L^3T^{-1}]} = [ML^{-1}T^{-1}]$.

List-$I$	List-$II$
$A$. Coefficient of viscosity	$I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension	$II$. $[ML^2T^{-2}]$
$C$. Pressure	$III$. $[ML^0T^{-2}]$
$D$. Surface energy	$IV$. $[ML^{-1}T^{-1}]$

Which of the following is the dimensional formula for viscosity?

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Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. Coefficient of viscosity $I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension $II$. $[ML^2T^{-2}]$
$C$. Pressure $III$. $[ML^0T^{-2}]$
$D$. Surface energy $IV$. $[ML^{-1}T^{-1}]$

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