(A) The erythro form is defined by having identical groups on the same side of the Fischer projection. In option $A$,both $-OH$ groups are on the same

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(A) The erythro form is defined by having identical groups on the same side of the Fischer projection. In option $A$,both $-OH$ groups are on the same side,which corresponds to the erythro configuration. Since the molecule lacks a plane of symmetry $(POS)$ and a center of symmetry $(COS)$,it is optically active.