(C) The reaction between $n$-butyl lithium $(C_4H_9Li)$ and tin$(II)$ chloride $(SnCl_2)$ involves the alkylation of the metal center.The balanced che

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(C) The reaction between $n$-butyl lithium $(C_4H_9Li)$ and tin$(II)$ chloride $(SnCl_2)$ involves the alkylation of the metal center.The balanced chemical equation is: $4C_4H_9Li + 2SnCl_2 \to ({C_4H_9})_4Sn + Sn + 4LiCl$.Thus,the product formed is tetrabutyltin,represented as $({C_4H_9})_4Sn$.