Which of the following is incorrect on the basis of the Ellingham diagram for carbon?

  • A
    Up to $710^{\circ}C$,the reaction of formation of $CO_2$ is energetically more favorable,but above $710^{\circ}C$,the formation of $CO$ is preferred.
  • B
    In principle,carbon can be used to reduce any metal oxide at a sufficiently high temperature.
  • C
    $\Delta S(C_{(s)} + 1/2 O_{2(g)} \to CO_{(g)}) < \Delta S(C_{(s)} + O_{2(g)} \to CO_{2(g)})$
  • D
    Carbon reduces many oxides at elevated temperature because the $\Delta G^{\circ}$ vs temperature line has a negative slope.

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Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: In the Ellingham diagram,a sharp change in slope of the line is observed for $Mg \rightarrow MgO$ at $\sim 1120^{\circ} C$.
Reason $R$: There is a large change of entropy associated with the change of state.
In the light of the above statements,choose the correct answer from the options given below.

In the process of extraction of gold,
Roasted gold ore $+ CN^{-} + H_2O \xrightarrow{O_2} [x] + OH^{-}$;
$[x] + Zn \rightarrow [y] + Au$
$[x]$ and $[y]$ are :

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Which of the following reactions takes place during the smelting process?

The Gibbs energy vs $T$ plot for the formation of oxides is given below:
For the given diagram,the correct statement is-

Steel contains $.....$ percent of carbon.

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