Which of the following is more basic than ani | vedclass

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(D) In aniline,the lone pair of electrons on the nitrogen atom is involved in resonance with the benzene ring,which decreases its availability for pro

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Benzylamine

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(D) In aniline,the lone pair of electrons on the nitrogen atom is involved in resonance with the benzene ring,which decreases its availability for protonation.In $p-$nitroaniline,the $-NO_2$ group is electron-withdrawing,further decreasing the basicity.In diphenylamine and triphenylamine,the lone pair is delocalized over two and three benzene rings respectively,making them even less basic than aniline.In benzylamine $(C_6H_5CH_2NH_2)$,the lone pair of electrons on the nitrogen atom is not involved in resonance with the benzene ring because it is separated by a $CH_2$ group.Therefore,benzylamine is more basic than aniline.

Which of the following is more basic than aniline?

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