Which of the following is more stable than th | vedclass

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions al

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Methyl anion

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions already possess a negative charge,the presence of electron-donating groups increases the electron density on the carbon atom,which destabilizes the carbanion. Therefore,the stability order is: $	ext{Methyl anion} > 	ext{Ethyl anion} > 	ext{Isobutyl anion} > t-	ext{Butyl anion}$. Among the given options,the methyl anion $(CH_3^-)$ is the most stable because it has no electron-donating alkyl groups attached to the negatively charged carbon.

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation

Which of the following is more stable than the remaining three?

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