Which of the following is not a correct statement for primary aliphatic amines?
- AThe intermolecular association in primary amines is less than the intermolecular association in secondary amines.
- BPrimary amines on treating with nitrous acid solution form corresponding alcohols except methyl amine.
- CPrimary amines are less basic than the secondary amines.
- DPrimary amines can be prepared by the Gabriel phthalimide synthesis.
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Similar Questions
The relation between $(A)$ and $(B)$ is:
$CH_3-CONH_2 \xrightarrow{KOBr} (A)$
$CH_3-CONH_2 \xrightarrow{LiAlH_4} (B)$
$CH_3-CONH_2 \xrightarrow{KOBr} (A)$
$CH_3-CONH_2 \xrightarrow{LiAlH_4} (B)$
Medium
View SolutionCompound $III$ is
$\xrightarrow[{ii)\,CuCl/HCl}]{{i)\,HNO_2\,(0 - 5\,^oC)}}I$ $\xrightarrow{{Sn/HCl}}II$ $\xrightarrow[{ii)\,H_3PO_2 + H_2O}]{{i)HNO_2\,(0 - 5\,^oC)\,}}III$
$\xrightarrow[{ii)\,CuCl/HCl}]{{i)\,HNO_2\,(0 - 5\,^oC)}}I$ $\xrightarrow{{Sn/HCl}}II$ $\xrightarrow[{ii)\,H_3PO_2 + H_2O}]{{i)HNO_2\,(0 - 5\,^oC)\,}}III$
Difficult
View SolutionThe product of the reaction is:
Difficult
View SolutionIn the chemical reaction $CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (a) + (b) + 3H_2O$,what are the products $(a)$ and $(b)$ respectively?
Medium
View Solution$9.3 \ g$ of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product '$P$'. The mass of product '$P$' obtained is $26.4 \ g$. The percentage yield is $......... \ \%$.
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