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(C) Intramolecular aldol condensation typically occurs in dicarbonyl compounds to form cyclic $\alpha,\beta$-unsaturated carbonyl compounds. Option $(

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Naphthalenone derivative

Vedclass · Answer

(C) Intramolecular aldol condensation typically occurs in dicarbonyl compounds to form cyclic $\alpha,\beta$-unsaturated carbonyl compounds. Option $(A)$ represents $1$-indanone,which can be formed from $2-(2-oxopropyl)benzaldehyde$. Option $(B)$ represents $2$-cyclohexenone,which can be formed from $heptane-2,6-dione$. Option $(C)$ represents a structure that is not typically formed via simple intramolecular aldol condensation of a single dicarbonyl precursor,as it often requires cross-aldol conditions or specific precursors not commonly classified under standard intramolecular cyclization. Option $(D)$ represents a bicyclic system that can be formed via Robinson annulation (a type of intramolecular aldol condensation). Therefore,$(C)$ is the correct answer.

Column $I$	Column $II$
$A$. $Ph-N_2Cl + Ph-OH \xrightarrow{NaOH/H_2O, 0^{\circ}C} Ph-N=N-Ph-OH$	$p$. Racemic mixture
$B$. $Pinacol \xrightarrow{H_2SO_4} Pinacolone$	$q$. Addition reaction
$C$. $Ph-CO-CH_3 \xrightarrow{1. LiAlH_4, 2. H_3O^+} Ph-CH(OH)-CH_3$	$r$. Substitution reaction
$D$. $4-chlorocyclohexanethiol \xrightarrow{Base} Thiacycloheptane$	$s$. Coupling reaction
	$t$. Carbocation intermediate

Which of the following is not the product of an intramolecular aldol condensation?

Similar Questions

The correct order of rate of reaction toward nucleophilic addition reaction for the following compounds is:
$(a)$ $p-NO_2-C_6H_4-CHO$
$(b)$ $C_6H_5-CHO$
$(c)$ $p-OMe-C_6H_4-CHO$
$(d)$ $CH_3-CO-CH_2CH_3$
$(e)$ $C_6H_5-CO-C_6H_5$

Which of the following cannot give a yellow $ppt.$ with $I_2/NaOH$?

Which of the following aldehydes is less reactive towards nucleophilic addition reaction?

$2(CHO-COOH) \xrightarrow{NaOH} CH_2OH-COOH + HOOC-COONa$. This reaction is:

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