Which of the following is obtained as the maj | vedclass

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(A) The reaction between methane $(CH_4)$ and chlorine $(Cl_2)$ in the presence of $UV$ light is a free radical substitution reaction.When methane is

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Chloromethane

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(A) The reaction between methane $(CH_4)$ and chlorine $(Cl_2)$ in the presence of $UV$ light is a free radical substitution reaction.When methane is in excess and chlorine is limited,the probability of a chlorine radical colliding with a methane molecule is much higher than colliding with a chloromethane molecule.Therefore,the reaction stops primarily at the first substitution step:$CH_4 + Cl_2 \xrightarrow{UV 	ext{ light}} CH_3Cl + HCl$Thus,chloromethane $(CH_3Cl)$ is obtained as the major product.

Which of the following is obtained as the major product when an excess of methane is treated with a limited amount of chlorine in the presence of $UV$ light?

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