Which of the following is obtained by the hyd | vedclass

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(C) Step $1$: Hydroboration-oxidation is an anti-Markovnikov addition of water across a double bond.Step $2$: The reaction of $propene$ $(CH_3-CH=CH_2

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$Propan-1-ol$

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(C) Step $1$: Hydroboration-oxidation is an anti-Markovnikov addition of water across a double bond.Step $2$: The reaction of $propene$ $(CH_3-CH=CH_2)$ with $BH_3$ followed by oxidation with $H_2O_2/OH^-$ results in the addition of $-OH$ to the less substituted carbon atom.Step $3$: This process yields $propan-1-ol$ $(CH_3-CH_2-CH_2OH)$ as the major product.

Which of the following is obtained by the hydroboration-oxidation of $propene$?

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