Which of the following is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of $O_2$ ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2,

Vedclass · Accepted Answer

$O_2$

Vedclass · Answer

(D) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of $O_2$ ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. Since $O_2$ contains two unpaired electrons in the $\pi^*$ antibonding orbitals,it exhibits paramagnetic behavior. In contrast,$N_2$ ($14$ electrons),$H_2$ ($2$ electrons),and $Li_2$ ($6$ electrons) have all paired electrons,making them diamagnetic.

Similar Questions

Give features of Molecular Orbital $(MO)$ theory:

What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

The correct statement regarding $SO_2$ molecule is

The bond lengths of $C_2$,$N_2$ and $B_2$ molecules are $X_1$,$X_2$ and $X_3$ $pm$ respectively. The correct order of their bond lengths is

Which of the following species exhibits the diamagnetic behaviour?

Vedclass Test Series

Exam Paper Generator

Online Exam Module