Which of the following is the correct order o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acidic strength of carboxylic acids is determined by the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ e

Vedclass · Accepted Answer

$CF_3COOH > CHCl_2COOH > HCOOH > C_6H_5CH_2COOH > CH_3COOH$

Vedclass · Answer

(A) The acidic strength of carboxylic acids is determined by the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) increase acidity by stabilizing the negative charge,while electron-donating groups ($+I$ effect) decrease acidity.The order of $-I$ effect strength is $CF_3 > CHCl_2 > H > C_6H_5CH_2 > CH_3$.$CF_3$ is a very strong electron-withdrawing group,making $CF_3COOH$ the strongest acid.$CHCl_2$ is also electron-withdrawing,making $CHCl_2COOH$ stronger than $HCOOH$.$HCOOH$ is stronger than $C_6H_5CH_2COOH$ (where the phenyl group has a slight $+I$ effect) and $CH_3COOH$ (where the methyl group has a $+I$ effect).Thus,the correct order is $CF_3COOH > CHCl_2COOH > HCOOH > C_6H_5CH_2COOH > CH_3COOH$.

Which of the following is the correct order of acidic strength?

Similar Questions

Statement-$I$: Most carboxylic acids exist as dimers in vapour phase or in aprotic solvents due to intermolecular hydrogen bonding.
Statement-$II$: Higher carboxylic acids are practically insoluble in water due to the increased hydrophobic interaction of the hydrocarbon part.

Identify the product of the following reaction:

Which of the following compounds is obtained when acyl chloride is hydrolysed with water?

What are $X$ and $Y$ respectively in the following reaction sequence?
$C_6H_5CH_3$ $\xrightarrow{X} C_6H_5CO_2H$ $\xrightarrow{Y} C_6H_5CH_2OH$

$Methyl$ propanoate on hydrolysis with dil. $NaOH$ forms a salt which on further acidification with conc. $HCl$ forms . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module