Which of the following is the smallest cation | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The ionic radii of isoelectronic species decrease as the nuclear charge increases. For the given ions: $Na^{+}$ ($10$ electrons,$Z=11$) $Mg^{+2}$

Vedclass · Accepted Answer

$Al^{+3}$

Vedclass · Answer

(D) The ionic radii of isoelectronic species decrease as the nuclear charge increases. For the given ions: $Na^{+}$ ($10$ electrons,$Z=11$) $Mg^{+2}$ ($10$ electrons,$Z=12$) $Al^{+3}$ ($10$ electrons,$Z=13$) $Ca^{+2}$ ($18$ electrons,$Z=20$) Comparing the isoelectronic series $(Na^{+}, Mg^{+2}, Al^{+3})$,the ionic radius decreases as the atomic number increases. Thus,$Al^{+3}$ is the smallest among the isoelectronic ions. $Ca^{+2}$ has a larger shell $(n=3)$ compared to the others $(n=2)$,making it significantly larger. The order of ionic radii is $Ca^{+2} > Na^{+} > Mg^{+2} > Al^{+3}$. Therefore,$Al^{+3}$ is the smallest cation.

Which of the following is the smallest cation?

Similar Questions

Which of the following elements in $+1$ oxidation state has the largest ionic radius?

The correct order of the decreasing ionic radii among the following isoelectronic species is

Which of the following is the incorrect order of ionic radius?

The correct order of increasing ionic radii is .... .

$K^{+}$,$Cl^{-}$,$Ca^{2+}$,and $S^{2-}$ ions are isoelectronic. The decreasing order of their ionic radii is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module