Which of the following isomers of C_4H_9Br is | vedclass

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(B) chiral molecule is one that contains at least one chiral carbon atom (a carbon atom bonded to four different groups).$n$-Butyl bromide: $CH_3-CH_2

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$sec$-Butyl bromide

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(B) chiral molecule is one that contains at least one chiral carbon atom (a carbon atom bonded to four different groups).$n$-Butyl bromide: $CH_3-CH_2-CH_2-CH_2Br$ (No chiral carbon).$sec$-Butyl bromide: $CH_3-CH(Br)-CH_2-CH_3$. The carbon atom marked with an asterisk $({}^*)$ is bonded to four different groups: $-H, -CH_3, -Br, -CH_2CH_3$. Thus,it is chiral.Isobutyl bromide: $(CH_3)_2CH-CH_2Br$ (No chiral carbon).$tert$-Butyl bromide: $(CH_3)_3CBr$ (No chiral carbon).Therefore,$sec$-butyl bromide is the chiral molecule.

Which of the following isomers of $C_4H_9Br$ is a chiral molecule?

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