Which of the following mixtures will have the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the lowest $pH$, we analyze the nature of each mixture:$(A)$ $10 \ mL$ $0.05 \ N$ $CH_{3}COOH$ $(0.5 \ mmol)$ + $5 \ mL$ $0.1 \ N$ $N

Vedclass · Accepted Answer

$5 \ mL$ $0.1 \ N$ $CH_{3}COOH + 10 \ mL$ $0.05 \ N$ $CH_{3}COONa$

Vedclass · Answer

(C) To determine the lowest $pH$, we analyze the nature of each mixture:$(A)$ $10 \ mL$ $0.05 \ N$ $CH_{3}COOH$ $(0.5 \ mmol)$ + $5 \ mL$ $0.1 \ N$ $NH_{4}OH$ $(0.5 \ mmol)$ forms a salt of weak acid and weak base $(CH_{3}COONH_{4})$, which is nearly neutral.$(B)$ $5 \ mL$ $0.2 \ N$ $NH_{4}Cl$ + $5 \ mL$ $0.2 \ N$ $NH_{4}OH$ forms a basic buffer $(pH > 7)$.$(C)$ $5 \ mL$ $0.1 \ N$ $CH_{3}COOH$ $(0.5 \ mmol)$ + $10 \ mL$ $0.05 \ N$ $CH_{3}COONa$ $(0.5 \ mmol)$ forms an acidic buffer where $pH = pK_{a} + \log(\frac{[Salt]}{[Acid]})$. Since $[Salt] = [Acid]$, $pH = pK_{a} \approx 4.76$.$(D)$ $5 \ mL$ $0.1 \ N$ $CH_{3}COOH$ + $5 \ mL$ $0.1 \ N$ $NaOH$ forms $CH_{3}COONa$, which undergoes anionic hydrolysis, resulting in a basic solution $(pH > 7)$.Comparing these, the acidic buffer in option $(C)$ has the lowest $pH$.

Which of the following mixtures will have the lowest $pH$ at $298 \ K$?

Similar Questions

$A$ certain buffer solution contains equal concentration of $X^{-}$ and $HX$. The $K_b$ for $X^{-}$ is $10^{-10}$. The $pH$ of the buffer is

$A$ solution which is resistant to change of $pH$ upon the addition of an acid or a base is known as

$A$ buffer solution is prepared by mixing $10 \ mL$ of $1.0 \ M$ acetic acid and $20 \ mL$ of $0.5 \ M$ sodium acetate and then diluted to $100 \ mL$ with distilled water. The $pH$ of the buffer solution is ($pK_a$ of acetic acid is $4.76$).

Buffer solutions have constant acidity and alkalinity because

$50 \ mL$ of $0.02 \ M$ $NaOH$ solution is mixed with $50 \ mL$ of $0.06 \ M$ acetic acid solution. The $pH$ of the resulting solution is $......$ ($pK_a$ of acetic acid is $4.76$,$\log 2 = 0.30$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module