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(C) To find the number of lone pairs $(LP)$ on the central atom,we use the formula: $LP = \frac{1}{2} (V - N)$,where $V$ is the number of valence elec

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$XeF_5^+$

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(C) To find the number of lone pairs $(LP)$ on the central atom,we use the formula: $LP = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (monovalent atoms + charge adjustment).$1. BrF_3$: Central atom $Br$ $(V=7)$. $LP = \frac{1}{2} (7 - 3) = 2 \ LP$.$2. BrF_4^-$: Central atom $Br$ $(V=7+1=8)$. $LP = \frac{1}{2} (8 - 4) = 2 \ LP$.$3. XeF_5^+$: Central atom $Xe$ $(V=8-1=7)$. $LP = \frac{1}{2} (7 - 5) = 1 \ LP$.$4. I_3^-$: Central atom $I$ $(V=7+1=8)$. $LP = \frac{1}{2} (8 - 2) = 3 \ LP$.Comparing the values,$XeF_5^+$ has the minimum number of lone pairs $(1 \ LP)$.

Which of the following molecules/species has the minimum number of lone pairs on its central atom?

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