Which of the following molecules has zero dip | vedclass

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(C) The dipole moment $(\mu)$ of a molecule depends on its geometry and the polarity of its bonds.$HF$ is a polar molecule with a linear geometry,so $

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$BF_3$

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(C) The dipole moment $(\mu)$ of a molecule depends on its geometry and the polarity of its bonds.$HF$ is a polar molecule with a linear geometry,so $\mu 
eq 0$.$NH_3$ has a trigonal pyramidal geometry with a lone pair on the nitrogen atom,resulting in a net dipole moment $(\mu = 1.48 \ D)$.$BF_3$ has a trigonal planar geometry. The three $B-F$ bonds are arranged at an angle of $120^{\circ}$ to each other. The vector sum of the dipole moments of the three $B-F$ bonds is zero,making the molecule non-polar $(\mu = 0)$.$CHCl_3$ is a polar molecule with a tetrahedral geometry where the bond dipoles do not cancel out $(\mu = 1.04 \ D)$.Therefore,$BF_3$ has a zero dipole moment.

Which of the following molecules has zero dipole moment?

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