Which of the following on heating gives an et | vedclass

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(D) The Williamson ether synthesis involves the reaction of an alkoxide ion with a primary alkyl halide to form an ether.$(P)$ $C_6H_5CH_2Br + CH_3ONa

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Both $(P)$ and $(Q)$

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(D) The Williamson ether synthesis involves the reaction of an alkoxide ion with a primary alkyl halide to form an ether.$(P)$ $C_6H_5CH_2Br + CH_3ONa \rightarrow C_6H_5CH_2OCH_3 + NaBr$. This is a $S_N2$ reaction between a primary benzylic halide and a strong nucleophile,yielding an ether as the major product.$(Q)$ $C_6H_5ONa + CH_3Br \rightarrow C_6H_5OCH_3 + NaBr$. This is a $S_N2$ reaction between a phenoxide ion and a primary alkyl halide,yielding an ether as the major product.$(R)$ $(CH_3)_3CCl + CH_3ONa \rightarrow (CH_3)_2C=CH_2 + CH_3OH + NaCl$. Since $(CH_3)_3CCl$ is a tertiary alkyl halide,the strong base $CH_3ONa$ promotes an $E2$ elimination reaction,giving an alkene as the major product.$(S)$ $C_6H_5CH=CHCl + CH_3ONa$. Vinyl halides are unreactive towards $S_N2$ reactions due to the partial double bond character of the $C-X$ bond and the instability of the vinylic carbocation,so no ether is formed.Therefore,both $(P)$ and $(Q)$ give an ether as the major product.

Which of the following on heating gives an ether as the major product?
$(P)$ $C_6H_5CH_2Br + CH_3ONa$
$(Q)$ $C_6H_5ONa + CH_3Br$
$(R)$ $(CH_3)_3CCl + CH_3ONa$
$(S)$ $C_6H_5CH=CHCl + CH_3ONa$

Similar Questions

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$(iv)$ $1-Methoxyethane$

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Which of the following on heating gives an ether as the major product?$(P)$ $C_6H_5CH_2Br + CH_3ONa$$(Q)$ $C_6H_5ONa + CH_3Br$$(R)$ $(CH_3)_3CCl + CH_3ONa$$(S)$ $C_6H_5CH=CHCl + CH_3ONa$