Which of the following orders is correct?

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(C) $1$. For ionic size: $P^{3-} (1.71 \ \mathring{A}) > S^{2-} (1.40 \ \mathring{A}) > Ca^{2+} (1.00 \ \mathring{A}) > K^{+} (1.38 \ \mathri

Vedclass · Accepted Answer

$Al^{3+}_{(aq)} > Mg^{2+}_{(aq)} > Na^{+}_{(aq)}$ : Hydrated size

Vedclass · Answer

(C) $1$. For ionic size: $P^{3-} (1.71 \ \mathring{A}) > S^{2-} (1.40 \ \mathring{A}) > Ca^{2+} (1.00 \ \mathring{A}) > K^{+} (1.38 \ \mathring{A})$. The given order is incorrect.
$2$. For electrical conductance in aqueous solution: Conductance depends on ionic mobility. Smaller ions in the gas phase have higher charge density,leading to greater hydration. Thus,$Na^{+}_{(aq)}$ is the most hydrated and has the lowest mobility and conductance. The correct order is $Cs^{+} > Rb^{+} > K^{+} > Na^{+}$. The given order is incorrect.
$3$. For hydrated size: Higher charge density leads to more hydration. $Al^{3+}$ has the highest charge density,followed by $Mg^{2+}$ and $Na^{+}$. Thus,the hydrated size order is $Al^{3+}_{(aq)} > Mg^{2+}_{(aq)} > Na^{+}_{(aq)}$. This is correct.
$4$. For ionic mobility: Smaller hydrated ions have higher mobility. $F^{-}$ is most hydrated,so it has the lowest mobility. The order should be $I^{-} > Br^{-} > F^{-}$. The given order is incorrect.

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