Which of the following orders is correct?

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(D) $1$. $Cr^{+2}$ $(d^4)$ is a strong reducing agent because it changes to $Cr^{+3}$ ($d^3$,stable $t_{2g}^3$ configuration). $Fe^{+2}$ $(d^6)$ is a

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(D) $1$. $Cr^{+2}$ $(d^4)$ is a strong reducing agent because it changes to $Cr^{+3}$ ($d^3$,stable $t_{2g}^3$ configuration). $Fe^{+2}$ $(d^6)$ is a weaker reducing agent as it changes to $Fe^{+3}$ ($d^5$,stable half-filled configuration). Thus,$Cr^{+2} > Fe^{+2}$ is correct.$2$. $Mn^{+3}$ $(d^4)$ is a strong oxidising agent because it reduces to $Mn^{+2}$ ($d^5$,stable half-filled configuration). $Cr^{+3}$ $(d^3)$ is stable and does not easily reduce. Thus,$Mn^{+3} > Cr^{+3}$ is correct.$3$. In group $6$,stability of the highest oxidation state increases down the group. Therefore,$WO_3$ is more stable than $CrO_3$. Thus,$WO_3 > CrO_3$ is correct.

Column - $I$	Column - $II$
$(a)$ Copper	$(i)$ Non-metal
$(b)$ Fluorine	$(ii)$ Transition Metal
$(c)$ Silicon	$(iii)$ Lanthanoid
$(d)$ Cerium	$(iv)$ Metalloid

Similar Questions

Which of the following substances are colored even in the absence of $d-d$ transitions?

Which of the following represents the correct order of stability for the given oxidation states?

Match the element in column $I$ with that in column $II$.

Column - $I$ Column - $II$

$(a)$ Copper $(i)$ Non-metal

$(b)$ Fluorine $(ii)$ Transition Metal

$(c)$ Silicon $(iii)$ Lanthanoid

$(d)$ Cerium $(iv)$ Metalloid

Identify the correct match:

Identify the correct statement$(s)$ among the following.

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